Răspuns:
a) [tex]5\sqrt{3} +7\sqrt{3}-2\sqrt{3} =(5+7-2)\sqrt{3}=10\sqrt{3}[/tex]
b)[tex]\sqrt{5} +3\sqrt{5}-4\sqrt{5} =(1+3-4)\sqrt{5} =0[/tex]
c)-[tex]\sqrt{7} -4\sqrt{7}+3\sqrt{7} =(-1-4+3)\sqrt{7}= -2\sqrt{7}[/tex]
d)[tex]3\sqrt{2}*5\sqrt{3}*\sqrt{6}=(3*5*1) \sqrt{2*3*6} =15\sqrt{36}=15*6= 90[/tex]
e) [tex](6\sqrt{12} ):(3\sqrt{3} )-5=2\sqrt{4}-5=2*2-5=-1[/tex]
f)[tex]3\sqrt{2}+7\sqrt{6}:\sqrt{3} =3\sqrt{2} +7\sqrt{2}=10\sqrt{2}[/tex]
Explicație pas cu pas:
