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[tex]\it m(\widehat{DAB})=30^o\ (suplementul\ lui\ 150^o)\\ \\ \mathcal{A}_{AOB}=\dfrac{\mathcal{A}_{ABCD}}{4}=\dfrac{AD\cdot AB\cdot sin\widehat{DAB}}{2}=\dfrac{6\cdot8\cdot sin30^o}{4}}=6\cdot2\cdot\dfrac{1}{2}=6\ cm^2[/tex]
