Răspuns:
Explicație:
ms H2 SO4= 200g
c= 10%
masa NaOH
md H2SO4= c . ms : 100
md= 10 .200 : 100= 20g H2SO4
xg 20g
2NaOH + H2SO4= Na2 SO4 + 2H2O
2 .40g 98g
x= 80 . 20 : 98= 16,32 g NaOH
MNaOH=23 + 16 +1=40------> 40g/moli
MH2SO4=2 + 32 + 4.16=98-------> 98g/moli