Răspuns:
[tex]a = | \sqrt{3} | - 4 - | \sqrt{3} - 2| \\ a = \sqrt{3} - 4 - | \sqrt{3} - 2 | \\ \sqrt{1} < \sqrt{3} < \sqrt{4 } \\ 1 < \sqrt{3} < 2 \\ cum \: \sqrt{3} < 2 \: rezulta \: ca \: | \sqrt{3} - 2 | = - ( \sqrt{3} - 2) = - \sqrt{3} + 2 \\ a = \sqrt{3} - 4 - ( - \sqrt{3} + 2) \\ a = \sqrt{3} - 4 + \sqrt{3} - 2 = 2 \sqrt{3} - 6[/tex]
