Răspuns:
Explicație pas cu pas:
A = {x ∈ R I IxI < 4}
IxI < 4 <=> -4 < x < 4 => A = (-4 ; 4)
B = {x ∈ R I Ix-1I ≤ 5}
Ix-1I ≤ 5 <=> -5 ≤ x-1 ≤ 5 <=> -4 ≤ x ≤ 6 => B = [-4 ; 6]
C = {x ∈ R I -3 ≤ 2x-1 ≤ 5}
-3 ≤ 2x-1 ≤ 5 <=> -2 ≤ 2x ≤ 6 <=> -1 ≤ x ≤ 3 => C = [-1 ; 3]
D = {x ∈ R I -5 ≤ x ≤ 0} => D = [-5 ; 0]
