Răspuns:
Explicație pas cu pas:
[tex]\it \dfrac{x+5}{x-7}+\dfrac{x+2}{x-1}=\dfrac{(x+5)(x-1)+(x+2)(x-7)}{(x-7)(x-1)}=\\ \\ \\ =\dfrac{x^2+4x-5+x^2-5x-14}{(x-7)(x-1)}=\dfrac{2x^2-x-19}{x^2-8x+7}[/tex]
