Anonimask Anonimask Matematică a fost răspuns e) 10x{24^2:576+3x[(3^2x2)^16:(3^29x2^15)+1^21]}:13 =f) 2^100:[2^50x2^48+(2^10x2^15)^5:2^27+(5^76:5^75-3)^90x2^8+2^98]g) [3^7x3^10+2^203:2^108-5x(5^2)^5]"(3^17+2^95-5^11)Dau coroana!Va rog urgent!!{ = acolada