TheFairyask
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rezolvati inecuatia in multimea numerelor intregi fara zero, care sunt doar negative:
4(x+1)+3(x+2)>x+1

Răspuns :

Targoviste44ask

[tex]\it 4(x+1)+3(x+2)>x+1 \Rightarrow 4(x+1)+3(x+2)-(x+1)>0 \Rightarrow \\ \\ \Rightarrow 3(x+1)+3(x+2)>0|_{:3} \Rightarrow x+1+x+2>0 \Rightarrow 2x+3>0 \Rightarrow \\ \\ \Rightarrow 2x>-3|_{:2} \Rightarrow x>-1,5\ \ \ \ \ (1)\\ \\ Dar,\ x<0\ \ \ \ \ (2)\\ \\ (1),\ (2) \Rightarrow x=-1[/tex]

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