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Rezolvati in multimea numerelor reale ecuatia 2log5(x-3)=log5(x-1)​

Răspuns :

Slavitescudoraask

log5(x-3)^2 = log5(x-1)

(x-3)^2= x-1

x^2-6x+9= x-1

x^2 -7x+10=0

delta= 49-40= 9

x1=(7+3)/2= 10/2=5

x×= (7-3)/2= 4/2=2

S={2,5}

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