Răspuns: Adevarat
[tex]\bf a = 2^{10}\cdot 3^{6} :6^{8}[/tex]
[tex]\bf a = 2^{10}\cdot 3^{6} :\big(2^{8}\cdot 3^{8}\big)[/tex]
[tex]\bf a = 2^{10-8}\cdot 3^{6-8}[/tex]
[tex]\bf a = 2^{2}\cdot 3^{-2}[/tex]
[tex]\bf a = 2^{2}\cdot \dfrac{1}{3^{2}}[/tex]
[tex]\bf a = \dfrac{2^{2}}{3^{2}}[/tex]
[tex]\red{\boxed{\bf a = \bigg(\dfrac{2}{3}\bigg)^{2}\implies patrat ~perfect}}[/tex]
