Răspuns :
[tex]\it \sqrt[n]{x^k}=x^{\frac{k}{n}}\\ \\ a)\ \sqrt{17}=17^\frac{1}{2};\ \ b)\ \sqrt[3]{19}=19^\frac{1}{3};\ \ c)\ \sqrt[4]{3^7}=3^{\frac{7}{4}};\ \ d)\ \sqrt[5]{\Big(\dfrac{3}{16}\Big)^2}=\Big(\dfrac{3}{16}\Big)^{\frac{2}{5}}\\ \\ \\ e)\ \sqrt[7]{\Big(\dfrac{-5}{17}\Big)^{-3}}=\Big(-\dfrac{5}{17}\Big)^{-\frac{3}{7}}=-\Big(\dfrac{17}{5}\Big)^{\frac{3}{7}}[/tex]