Răspuns :
[tex]\it \dfrac{^{15)}1}{\ \ 2}+\dfrac{^{10)}1}{\ \ 3}+\dfrac{^{6)}1}{\ \ 5}=\dfrac{15+10+6}{30}=\dfrac{31}{30}=1\dfrac{1}{30}[/tex]
[tex]\it \dfrac{^{15)}1}{\ \ 2}+\dfrac{^{10)}1}{\ \ 3}+\dfrac{^{6)}1}{\ \ 5}=\dfrac{15+10+6}{30}=\dfrac{31}{30}=1\dfrac{1}{30}[/tex]