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A. 3x(√3+√5)-x(3√5-2√3)=2√3(x+3√5)
B. 2√3(x+√6)-x(√3+1)=7√2-x
C. 5√2(x-√8)-2(x-5)=x(3√2-2)

Răspuns :

MFMask
a) desfacand parantezele⇒
3x√3+3x√5-3x√5+2x√3=2x√3+6√3.√5
simplificand⇒
3x√3=6√3√5
x=2√5

b)2x√3+6√2-x√3-x=7√2-x
reducand
x√3=√2
x=√6/3

c)5x√2-5.4-2x+10=3x√2 -2x
5x√2-10-3x√2=0
2x√2=10
x√2=5
x=5√2/2

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