ex3
a) 9x-5(x+4)=7(x-8)-24+x
9x-5x-20=7x-56-24+x
4x-20=8x-80
4x-8x=(-80)+20
-4x=-60
x=15
b)amplificam toate fractiile cu 60 si obtinem
2(7x+6)-5(2x-9)=2(2x+13)-3(x+8)+40
14x+12-10x+45=4x+26-3x-24+40
4x+57=x+42
4x-x=42-57
3x=-15
x=-5
c) -/-2x-5/=-4-13
-/-2x-5/=-17
/2x-5/=17
-2x-5=17 sau -2x-5=-17
x=-11 sau x=6
Sper ca te-am ajutat macar cu ceva:)
