Răspuns:
[tex]( \frac{9}{ \sqrt{3} } - 2 \sqrt{3} ) \times \frac{3}{4} + \sqrt{ \frac{169}{16} } = \\ ( \frac{9 \sqrt{3} }{3} - 2 \sqrt{3} ) \times \frac{3}{4} + \frac{13}{4} = \\ (9 \sqrt{3} - 6 \sqrt{3} ) \times \frac{3}{4} + \frac{13}{4} = \\ \frac{9 \sqrt{3} }{4} + \frac{13}{4} = \frac{13 + 9 \sqrt{3} }{4} [/tex]
