Nixeyaf953ask
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calculati : b) 3 la 10 × 2 la 10 - 6 la 11 ÷6 =?! c) 10 la puterea 33 ÷ 5 la puetrea 33 ÷ 2 la puterea a doua totul la a 5 a=?!!! plzzzz dau coroana​​

Răspuns :

Florin3364ask

Răspuns:

Explicație pas cu pas:

b)

[tex]3^{10}*2^{10}-6^{11}:6 = (3*2)^{10} - 6^{11-1} = 6^{10} - 6^{10} =0[/tex]

c)

[tex](10^{33}:5^{33}:2^2)^5=\\\\=(\frac{10^{33}}{5^{33}}:2^2)^5=\\\\=[(\frac{10}{5})^{33}:2^2]^5=\\\\=[(\frac{10}{5})^{33}:2^2]^5=\\\\=(2^{33}:2^2)^5=\\\\=(2^{33-2})^5=\\\\=(2^{31})^5=\\\\=2^{31*5}=\\\\=2^{155}[/tex]

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