(2⁵+2²):(2²+2¹)+2²+2¹+2⁰-1²⁰¹⁵ =
= (32+4) : (4+2) + 4 + 2 + 1 - 1 =
= 36 : 6 + 6 =
= 6 + 6 = 12
[tex](2^5+2^2):(2^2+2^1)+2^2+2^1+2^0-1^{2015}=\\= (2^2(2^3+1)):(4+2)+4+2+1-1=\\=4(8+1):6+6=\\=4\cdot 9:6+6=\\=36:6+6=\\=6+6=\boxed{12}[/tex]
