Răspuns :
in ΔABD dr. in B
⇒T.I. BM=MD*MA
BM=16*9
BM=144
⇒T.C. AB patrat=AD*AM
=25*9
=225
AB=15
in ΔABD dr. in B⇒T.P [tex]AB ^{2} +BD ^{2} =AD ^{2} [/tex]
225+[tex]BD ^{2} [/tex]=625
BD la patrat=400
BD=20 (BD este inaltimea)
Aria=b*h
=15*20=300
⇒T.I. BM=MD*MA
BM=16*9
BM=144
⇒T.C. AB patrat=AD*AM
=25*9
=225
AB=15
in ΔABD dr. in B⇒T.P [tex]AB ^{2} +BD ^{2} =AD ^{2} [/tex]
225+[tex]BD ^{2} [/tex]=625
BD la patrat=400
BD=20 (BD este inaltimea)
Aria=b*h
=15*20=300