Răspuns:
Explicație pas cu pas:
a)
[tex](1\frac{1}{5})^2 - (\frac{7}{10})^2 +(1\frac{1}{5} -\frac{7}{10})^2=[/tex]
[tex]=(\frac{6}{5})^2 - (\frac{7}{10})^2 +(\frac{6}{5} -\frac{7}{10})^2=[/tex]
[tex]=\frac{36}{25} - \frac{49}{100} +(\frac{12}{10} -\frac{7}{10})^2=[/tex]
[tex]=\frac{144}{100} - \frac{49}{100} +(\frac{12-7}{10})^2=[/tex]
[tex]=\frac{144-49}{100}+(\frac{5}{10})^2=[/tex]
[tex]=\frac{95}{100}+(\frac{1}{2})^2=[/tex]
[tex]=\frac{19}{20}+\frac{1}{4}=[/tex]
[tex]=\frac{19}{20}+\frac{5}{20}=[/tex]
[tex]=\frac{19+5}{20} =[/tex]
[tex]=\frac{24}{20} =[/tex]
[tex]=1,2[/tex]
b)
[tex][(-\frac{1}{2})^3]^6 :(0,5)^{12} - \frac{1}{32} =[/tex]
[tex]=(-\frac{1}{2})^{18} :(\frac{1}{2})^{12} - \frac{1}{32} =[/tex]
[tex]=(-1)^{18}*(\frac{1}{2})^{18} :\frac{1}{2^{12}} - \frac{1}{32} =[/tex]
[tex]=\frac{1}{2^{18}}*{2^{12} - \frac{1}{32} =[/tex]
[tex]=\frac{1}{2^{6}} - \frac{1}{32} =[/tex]
[tex]=\frac{1}{64} - \frac{1}{32} =[/tex]
[tex]=\frac{1}{64} - \frac{2}{64} =[/tex]
[tex]=\frac{1-2}{64}=[/tex]
[tex]=-\frac{1}{64}[/tex]
