Salut!
Răspuns:[tex] \bf \big \: S= (2 \sqrt{3} ;-6 \sqrt{3} )[/tex]✅
[tex] \bf |x + 2 \sqrt{3} | = 4 \sqrt{3} = > 1)x + 2 \sqrt{3 } = 4 \sqrt{3} \: sau \: 2)x + 2 \sqrt{3 } = - 4 \sqrt{3} [/tex]
[tex] \bf \:1) x + 2 \sqrt{3} = 4 \sqrt{3} \rightarrow \: x = 4 \sqrt{3} - 2 \sqrt{3} = > x = 2 \sqrt{3} [/tex]
[tex] \bf \: 2)x + 2 \sqrt{ 3 } = - 4 \sqrt{3} \rightarrow \: x = - 4 \sqrt{3} - 2 \sqrt{3} = > x = - 6 \sqrt{3} [/tex]
[tex] \bf \big \: S= (2 \sqrt{3} ;-6 \sqrt{3} )[/tex]☑️
