am nevoie de ajutor va rog

4x=5y

2x+3y
---------- = ?
x+4y


Răspuns :

Salut!

[tex]\bf 4x = 5y => x = \frac{5y}{4}[/tex][tex]\bf \frac{2 \times \frac{5y}{4}+ ^{4)} (3y) }{\frac{5y}{4}+^{4)} (4y) } = \frac{\frac{10y+12y}{4}}{\frac{5y+16y}{4}} ={\frac{10y+12y}{4}}\div{\frac{5y+16y}{4}}={\frac{10y+12y}{\not4}}\times{\frac{\not4}{5y+16y}}=\frac{10y+12y}{5y+16y}=\frac{22\not y}{21\not y} = \frac{22}{21}[/tex]