Răspuns:
2×56g................... 2×162,5g
2Fe + 3Cl2 => 2 FeCl 3
112g...... ...................xg
MFe=56g/mol
MFeCl3= 56+3×35,5=162,5g/mol
x=112×2×162,5/1×56= 325g FeCl3