c) , d) și e) cu rezolvare.

C D Și E Cu Rezolvare class=

Răspuns :

Răspuns:

c)

[tex]=(\frac{23*4+31*7}{63*4}-\frac{21*3+4*5}{4*21} )*48:(\frac{3}{5} *\frac{8}{7} )=[/tex]

[tex]=(\frac{92+217-3*(63+20)}{4*63} )*48:\frac{24}{35}=[/tex]

[tex]=(\frac{309-249)}{4*63} )*48*\frac{35}{24}=[/tex]

[tex]=\frac{60}{4*63} *2*35=[/tex]

[tex]=\frac{15}{7*9} *2*5*7=[/tex]

[tex]=\frac{5}{3} *2*5=[/tex]

[tex]=\frac{50}{3}[/tex]

d)

[tex]=[(\frac{5*17+9*3}{120} -\frac{5*11+31*3}{240} ):\frac{19}{5} ]*\frac{12}{7} =[/tex]

[tex]=[\frac{2*(85+27)-55-93}{240}*\frac{5}{19} ]*\frac{12}{7} =[/tex]

[tex]=(\frac{224-148}{48}*\frac{1}{19} )*\frac{12}{7} =[/tex]

[tex]=\frac{76}{48}*\frac{1}{19} *\frac{12}{7} =[/tex]

[tex]=\frac{1}{7}[/tex]

e)

[tex]=\frac{1}{2} +\frac{1}{2} :(\frac{2+3}{2} *8-\frac{1}{2} *4*8)=[/tex]

[tex]=\frac{1}{2} +\frac{1}{2} :(5*4-2*8)=[/tex]

[tex]=\frac{1}{2} +\frac{1}{2} :4=[/tex]

[tex]=\frac{1}{2} +\frac{1}{2} *\frac{1}{4} =[/tex]

[tex]=\frac{1}{2} +\frac{1}{8} =[/tex]

[tex]=\frac{4+1}{8} =[/tex]

[tex]=\frac{5}{8}[/tex]

Explicație pas cu pas: