[tex]-1\frac{1}{6}-(2 \frac{1}{8}+\frac{7}{2})-1,0(6)=-\frac{7}{6}-(\frac{17}{8}+\frac{7}{2})-\frac{16}{15}= \\ =-\frac{7}{6}-\frac{17+28}{8}-\frac{16}{15}=-\frac{7}{6}-\frac{45}{8}-\frac{16}{15}=-\frac{28}{24}-\frac{135}{24}-\frac{16}{15}= \\ =-\frac{163}{24}-\frac{16}{15}=-\frac{815}{120}-\frac{6 \ 520}{120}=-\frac{7 \ 335}{120}=-\frac{1 \ 467}{24}=\boxed{-\frac{489}{8}}[/tex]
