Notăm triunghiul ABC, cu AB=AC=51cm, BC=48cm.
Aplicăm formula lui Heron:
[tex]\it \mathcal{A}=\sqrt{p(p-a)(p-b)(p-c)}\\ \\ p=\dfrac{51+51+48}{2}=75\\ \\ p-a=75-48=27\\ \\ p-b=p-c=75-51=24\\ \\ \\ \mathcal{A}=\sqrt{75\cdot27\cdot24\cdot24}=\sqrt{25\cdot3\cdot27\cdot24^2}=\sqrt{25\cdot81\cdot24^2}=5\cdot9\cdot24=\\ \\ =9\cdot120=1080\ cm^2[/tex]
