16. Primul nr=a
Al doilea nr=b
a+b=182
a:b= 5 rest 8 => a=5b+8
inlocuim deci vine 5b+8+b=182
6b+8=182
6b=182-8=174
b=174:6 => b=29 => a=5x29+8=153
17. primul nr=a
al doilea nr=b
a-b=308
a:b=8 rest 35 => a=8b+35
inlocuim , deci 8b+35-b=308
7b+35=308
7b=273
b=39 => a=39x8+35=347
18.a) 1961: x=53
x=1961:53
x=37
