Răspuns:
a) f(x)=3x²+2x+1
f'(x)=(3x²+2x+1)'
f'(x)=(3x²)'+(2x)'+(1)'
f'(x)=3*2*x+2+0
f'(x)=6x+2
b)f(x)=4x³-5x²+6x+5
f'(x)=(4x³)'-(5x²)'+(6x)'+(5)'
f'(x)=(4*3*x²)-(5*2*x)+6+0
f'(x)=12x²-10x+6
c)f(x)=5x⁴+3x-1/x
f'(x)=(5x⁴)'+(3x)'-(x⁻¹)'
f'(x)=(5*4*x³)+3+(1/(x²))
f'(x)=20*x³+(1/(x²))+3
