Răspuns:
Explicație pas cu pas:
[tex]\it \bf{a)}\ \it 3\sqrt5:10^{-1}-\dfrac{60}{\sqrt5}+\sqrt{720}-5^{-1}\cdot\sqrt{4500}=3\sqrt5:\dfrac{1}{10}-\dfrac{60\sqrt5}{5}+\\ \\ \\ +\sqrt{144\cdot5}-\dfrac{1}{5}\cdot\sqrt{900\cdot5}=\sqrt5(30-12+12-6)=24\sqrt5[/tex]
