2. (g*f)(1) = g(f(1)) = g(0) = 0-3 = -3
f(1) = 1-3+2 = -2+2 = 0
5. Fie H centrul de greutate a triunghiului ABC
xH = (xA+xB+xC)/3 = (4+3+8)/3 = 15/3 =5
yH = (yA+yB+yC)/3 = (6+2+1)/3 = 9/3 =3
Deci H(5, 3)
d(P,H) = PH = V(xH-xP)² + (yH-yP)² = V(5+1)² + (3+5)² = V(6² +8²) = V(36+64) = V100 = 10
