Răspuns: Ai rezolvarea mai jos
Explicație pas cu pas:
[tex]\bf a)~~~ A=3^{15}+3^{16}+3^{17}[/tex]
[tex]\bf Dam~ factor~ comun~ pe~ 3^{15}[/tex]
[tex]\bf A = 3^{15}\cdot \Big(3^{15-15}+3^{16-15} + 3^{17-15}\Big)[/tex]
[tex]\bf A = 3^{15}\cdot \Big(3^{0}+3^{1} + 3^{2}\Big)[/tex]
[tex]\bf A = 3^{15}\cdot \Big(1+3 + 9\Big)[/tex]
[tex]\pink{\underline{\bf A = 3^{15}\cdot 13 \implies A~\vdots~13}}[/tex]
[tex]\it ~~[/tex]
[tex]\bf b)~~~B= 2^{22} +2^{24} +2^{26}[/tex]
[tex]\bf Dam~ factor~ comun~ pe~ 2^{22}[/tex]
[tex]\bf B = 2^{22}\cdot \Big(2^{22-22}+2^{24-22} + 2^{26-22}\Big)[/tex]
[tex]\bf B = 2^{22}\cdot \Big(2^{0}+2^{2} + 2^{4}\Big)[/tex]
[tex]\bf B = 2^{22}\cdot \Big(1+4 + 16\Big)[/tex]
[tex]\purple{\underline{\bf B = 2^{22}\cdot 21 \implies B ~\vdots~21}}[/tex]
[tex]\it~~[/tex]
[tex]\bf \star~\underline{\text{\bf Formule pentru puteri}}:[/tex]
[tex]\red{ \bf a^{0} = 1}[/tex]
[tex]\red{\bf (a^{n})^{m} = a^{n \cdot m}}[/tex]
[tex]\red{\bf a^{n}\cdot a^{m} =a^{n+m}}[/tex]
[tex]\red{\bf a^{n}: a^{m} =a^{n-m}}[/tex]
==pav38==
Baftă multă !
