[tex]\displaystyle\bf\\1)~~~SI~(AND)~~~~~Y=A\cdot B\\\\2)~~~SI~NEGAT (NAND)~~~~~Y=\overline{A\cdot B}\\\\3)~~~SAU~(OR)~~~~~Y=A+B\\\\4)~~~SAU ~NEGAT (NOR)~~~~~Y=\overline{A+B}\\\\5)~~~NEGARE (NOT)~~~~~Y=\overline{A}\\\\6)~~~SAU~ EXCLUSIV (XOR)~~~~~Y=\overline{A}B+A\overline{B}\\\\[/tex]
Ti-am scris rezolvarea mai sus in Latex\\
apoi am transpus totul in tabelul tau, pe care \\
l-am facut mai mare ca sa incapa si desenele portilor logice din problema.
