Răspuns:
2(x+y-1)x+3=y
3(2x+1)-4y=0
<=>
2x^2 +2xy -2x+3 -y=0
6x+3-4y=0 => y=(6x+3)/4
2x^2 +2x(6x+3)/4 -2x +3 -(6x+3)/4=0 |*4
8x^2 +2x(6x+3)-8x+12-(6x+3)=0
8x^2 +12x^2 +6x-8x+12-6x-3=0
20x^2-8x+9=0
delta=64-4*20*9=64-720 negativa nu are solutii
