Răspuns :
Răspuns:
Fie a, b, c, d€Z (numere intregi), consecutive =>
=> a=a
b=a+1
c=b+1=a+2
d=c+1=a+3
a+b+c+d=-50
a+a+1+a+2+a+3=-50
4a+6=-50
4a=-56
a=-14 => b=-13, c=-12, d=-11
Verificare:
-14-13-12-11=-50 (Adevarat)
Răspuns:
a+a+1+a+2+a+3=-50
4a=-50-6
a=-56:4
a=-14
-14+1=-13
-14+2=-12
-14+3=-11
cele patru numere sunt: -11 , -12 , -13 , -14