dolomit = CaMg(CO3)2
M = 40+24+2(12+3x16) = 184 g/mol
1 tona = 1000 kg
1000 kg dolomit impur ....................... 100%
m.impuritati .............................................. 10%
= 100 kg impuritati
=> m.pura = m.impura - m.impuritati = 1000 - 100 = 900 kg
184 g .......................... 24 g Mg
900x10la3 g ............... X = 117400 g Mg = 117,4 kg Mg