Leeadeea363ask
a fost răspuns

Calculați respectând ordinea efectuării operațiilor:
56:7+(7x4+2):10
303+303:3-303x(3-3)
(32+26+30+32):4
256-(70+28)
(87-54)x[(376:4):2]

Răspuns :

Andreutsa10ask

56:7+(7x4+2):10=

8+(28+2):10=

8+30:10=

8+3=11

303+303:3-303x(3-3)=

303+101-0=404

(32+26+30+32):4=

120:4=30

256-(70+28)=

256-98=158

(87-54)x[(376:4):2]=

33*(94:2)=

33*46=1518

Crintina72ask

Salutare!

56:7+(7x4+2):10=

56:7+(28+2):10=

56:7+30:10=

8+3=

11

303+303:3-303x(3-3)=

303+303:3-303×0=

303+101-0=

404-0=

404

(32+26+30+32):4=

(58+30+32):4=

(88+32):4=

120:4=

30

256-(70+28)=

256-98=

158

(87-54)x[(376:4):2]=

33×(94:2)=

33×47=

1551