[tex]\it a)\ -\dfrac{4}{9}:\Big(-\dfrac{2}{3}\Big)=+\dfrac{4}{9}\cdot\dfrac{3}{2}=\dfrac{\ 12^{(6}}{18}=\dfrac{2}{3}\\ \\ \\ b)\ \dfrac{2}{3}:\Big(-\dfrac{5}{9}\Big):\Big(+\dfrac{10}{3}\Big)=-\dfrac{2}{3}\cdot\dfrac{9}{5}\cdot\dfrac{3}{10}=-\dfrac{\ 54^{(6}}{150}=-\dfrac{9}{25}[/tex]
[tex]\it d)\ -\dfrac{3}{5}:0,2:\dfrac{9}{5}:0,5=-\dfrac{3}{5}:\dfrac{2}{10}:\dfrac{9}{5}:\dfrac{1}{2}=-\dfrac{3}{5}\cdot\dfrac{10}{2}\cdot\dfrac{5}{9}\cdot\dfrac{2}{1}=-\dfrac{\ 300^{(30}}{90}=\\ \\ \\ =-\dfrac{10}{3}[/tex]
