[tex]\it a)\ \ x+\dfrac{1}{3}=\dfrac{5}{3} \Rightarrow x=\dfrac{5}{3}-\dfrac{1}{3}=\dfrac{4}{3}\\ \\ \\ c)\ \ x-\dfrac{5}{6}=\dfrac{1}{6} \Rightarrow x=\dfrac{1}{6}-\dfrac{5}{6}=\dfrac{-4^{(2}}{6}=-\dfrac{2}{3}\\ \\ \\ b)\ \ x-\dfrac{1}{4}=\dfrac{5}{4} \Rightarrow x=\dfrac{5}{4}+\dfrac{1}{4}=\dfrac{\ \ 6^{(2}}{4}=\dfrac{3}{2}[/tex]
