Răspuns:
Explicație:
1.
ZnO
CaF2
Fe2 S3
H I
HBr
2.
MNaCl= 23 + 35,5=58,5-------> 58,5g/moli
MAgNO3= 108 + 14 + 3.16=170------> 170g/moli
MCuSO4= 64 + 32 + 4.16=160-------> 160g/moli
MCaCO3=40 + 12 + 3.16=100------->100g/moli
MNaOH= 23 +16 +1=40------->40g/moli
MCa(OH)2= 40 +2.16 +2= 74-------> 74g/moli
NaCl
r.a.=1 : 1
AgNO3
r.a.= 1 : 1 : 3
CuSO4
r.a.= 1 : 1 : 4
CaCO3
r.a.= 1 : 1 : 3
NaOH
r.a.= 1 : 1 :1
Ca(OH)2
r.a.= 1 :2 :2
3
CaCl2
Mg(OH)2
HBr
Al(NO3)3