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Cum se face problema asta?
Sa se determine x din egalitatea:{[(x+40:5):2^2+2^3x3^2]:2^2+2^2x5+3^2}:5^2-2^0=1

Răspuns :

PopoiuClaudiaask
{[(x+40:5):2^2+2^3x3^2]:2^2+2^2x5+3^2}:5^2-2^0=1
{[(x+40:5):4+8x9]:4+4x5+9}:25-1=1 / +1
{[(x+40:5):4+8x9]:4+4x5+9}:25=2 / x25
[(x+40:5):4+8x9]:4+4x5+9=50 / -9
[(x+40:5):4+8x9]:4+20=41 / -20
[(x+40:5):4+8x9]:4=21 / x4
(x+40:5):4+72=84 / -72
(x+8):4=12 / x4
X+8=48 / -8
x=40