[tex]\it d)\ \ \widehat J=30^o\ (complementul\ lui\ 60^o)\\ .\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (90^o-60^o=30^o)\\ \\ HJ=2\cdot3=6\ cm\ (cu\ Th.\ \angle\ 30^o),\ \ \ \ GJ=3\sqrt3\ cm\ (cu\ \ Th.\ Pitagora)\\ \\ e)\ \ \widehat R =180^o-(30^o+30^o)=120^o\\ \\ \Delta RST-isoscel \Rightarrow RS=RT=4\sqrt3\ (cu\ Th\ sinusurilor)[/tex]