[tex]\it 3x^2+2x-5=0\\ \\ \Delta=b^2-4ac=2^2-4\cdot3\cdot(-5)=4+60=64\\ \\ x_{1,2}=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\ \\ \\ x_{1,2}=\dfrac{-2\pm\sqrt{64}}{2\cdot3}=\dfrac{-2\pm8}{6}\\ \\ \\ x_1=\dfrac{-2-8}{8}=\dfrac{-10^{(2}}{6}=-\dfrac{5}{3}\\ \\ \\ x_2=\dfrac{-2+8}{6}=\dfrac{6}{6}=1[/tex]
