a fost răspuns

m=200g
ti=20°C-》 T1=20+273= 293 K
Ca=4180 J/kg×K
R= 20 omi
I= 100 mA
t= 20 minute
Aflați t2.

M200g Ti20C T120273 293 K Ca4180 JkgK R 20 Omi I 100 MA T 20 Minute Aflați T2 class=

Răspuns :

t2=293,15K=20°C

Q=418kJ=418000J

c=4180J/kg°C

m=?kg

Formule:

Q=c*m*Δt

Q=c*m*(t2-t1)

m=Q/c*(t2-t1)

Calcule:

m=418000/4180*(20-10)=10kg

Negrunastea1ask

Explicație:

T2=293,15k=20°C.

Q=418kj=41800j.

c=4180J\Kg°C

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