Răspuns :
[tex]AB=c=8 ,BC=a, AC=bA[ABC]=2bcsinA⇔ 203=2b⋅8sin60\textdegree⇔403=b⋅823⇔b=10a2=b2+c2−2bc⋅cos60\textdegreea2=100+64−2⋅8⋅10⋅21a2=164−80=84a=84=221a=221P=a+b+c=221+10+8=18+221[/tex]
[tex]AB=c=8 ,BC=a, AC=bA[ABC]=2bcsinA⇔ 203=2b⋅8sin60\textdegree⇔403=b⋅823⇔b=10a2=b2+c2−2bc⋅cos60\textdegreea2=100+64−2⋅8⋅10⋅21a2=164−80=84a=84=221a=221P=a+b+c=221+10+8=18+221[/tex]