a fost răspuns

rezolvati ecuatia                 [tex] \frac{4x-2}{3x+5} +4 \leq 0[/tex]

Răspuns :

⇒(4x-2)/(3x+5)≥-4
4x-2≥-4(3x+5)
4x+12x≥-60+2
16x≥-58
x≥-58/16 simplificam⇒x≥-29/8
x≥-3,625
x∈[-3,625; +α}

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