a fost răspuns

REZOLVATI IN Z INECUATIA 7(2x+3)-5(4-x)+12≤4(3x+4)+4
VA ROG AJUTATIMA DETALIAT !!!!!!!!!!!!!!!!!!!

Răspuns :

Miky93ask
14x +21 -20 +5x ≤12x +16 +4
19x +1 ≤12x +20
19x -12x ≤20-1
7x ≤19
x ≤19/7   ⇒x∈{ -19/7 ; 19/7}

AleStarryask
mai intai inmultesti parantezele 
14x + 21 - 20 + 5x + 12 ≤ 12x + 16 + 4
acum scazi 12x
2x + 1 + 5x + 12 ≤ 20
7x + 13 ≤ 20
scazi 13
7x ≤ 7
imparti la 7
x ≤ 1 => x ∈ { 1 , 0 , - 1 , -2 ,  ... }