Răspuns:
g) f(x)=(x-3)²+4
f'(x) = 2(x-3) = 2x-6
h) f(x)=(x+1)²+(x-2)³
f'(x) = 2(x+1)+3(x-2)² = 2x+2+3x²-12x+12 = 3x²-10x+14
i) fx) = 2√x+x√2
f'(x) =2·1/2·1/√x+√2 = 1/√x+√2
k) f(x) = -√x-3ln(x)+3ˣ
f'(x) == -1/2·1/√x-3/x+x·3ˣ⁻¹ = -1/(2√x)-3/x+x·3ˣ⁻¹
l) f(x)=√5-5√x+5cos(x)
f'(x) = 0-5·1/2·1/√x-5sin(x) = -5/(2√x)-5sin(x)
