La primul sistem aplica metoda substitutiei
x+3y = 5
3x-y = 25
x = 5-3y
3(5-3y)-y = 25
x=5-3y
15-9y-y=25
x=5-3y
-10y = 10
x= 5+3= 8
y= -1
La al doilea aplic metoda reducerii
2x-y= 3
x +y= 2
----------(+)
3x / = 5 => x= 5/3
5/3+y = 2 => y = 2-5/3 amplifici pe 2 cu 3
y= 6/3-5/3 = 1/3
