Răspuns:
Explicație pas cu pas:
[tex]\frac{7}{a-2b}- \frac{5}{a+2b}=\frac{7(a+2b)-5(a-2b)}{(a-2b)(a+2b)} = \frac{7a+14b-5a+10b}{a^2-4b^2}= \frac{2a+24b}{a^2-4b^2}[/tex]
b) [tex]\frac{(x-5)^2}{3(x+6)} * \frac{(x-6)(x+6)}{(x-5)(x+5)}= \frac{(x-5)(x-6)}{3(x+5)} = \frac{x^2-11x+30}{3x+15}[/tex]