Răspuns:
Explicație pas cu pas:
f : R → R ; f(x) = -ax + 3
g : R → R ; g(x) = 3x – b
A(1 ; 1) ∈ Gf ∩ Gg
A(1 ; 1) ∈ Gf <=> f(1) = 1 =>
-a+3 = 1 => a = 3-1 => a = 2
A(1 ; 1) ∈ Gg <=> g(1) = 1 =>
3-b = 1 => b = 3-1 => b = 2
f(x) ∩ g(x) <=>
-ax + 3 = 3x -b =>
-2·1+3 = 3·1-2 = 1 corect
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