Răspuns:
4x²-11lxl-3=0
4x²-11x-3=
{4x²-11x-3 pt x≥0
{4x²+11x-3 pt x<0
4x²-11x-3=0
Δ=11²-4*4*(-3)=
121+48=169
x1=(11-√169)/2*4=11-13)/8= -2/8=
-1/4
x2=(11+13)/8=24/8=3
Caz2
4x²+11x-3=0
x3=(-11-13)/8= -24/8 = -3
x4=(-11+13)/8=2/8= 1/4
S={-3,-1/4,1/4,3}
Explicație pas cu pas:
